How Differential Equations Relate to Physics Equations – Motion, Velocity, and Acceleration

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How does differential equations relate to physics equations?

Consider the second-order-linear-nonhomogeneous-ODE with constant coefficients,

$$c_1y”+c_2y’+c_3y=0.$$

So how does this relate to physics? Well, if distance is $x$, then velocity is $\dot{x}=x’=v$, and acceleration is $\ddot{x}=v’=a$. Assuming this is not constant acceleration or velocity, we will have functions of time. Thus,

$$c_1y”+c_2y’+c_3y=0\ \equiv\ c_1a(t)+c_2v(t)+c_3x(t)=0.$$

In physics, all of the kinematic equations of motion are differential equations that you are solving by plug and play. In a ODE course, you would solve these using ODE techniques.

In a physics course, the ‘plug and play’ approach to solutions would be something like, “Find the time the sums acceleration, velocity, and distance to zero when $a(t)=t^2$, $v(t)=t$, $x(t)=t-1$.”

$$a(t)+v(t)+x(t)=0 \ \Rightarrow\ t^2+t+t-1=t^2+2t-1=0 \ \Rightarrow\ t=-1\pm\sqrt{2}.$$

Time is positive, so we omit $-1-\sqrt{2}$ and keep $t_0=-1+\sqrt{2}\approx0.41\text{ s}$.

So, at $t=0.41\text{ s}$, the summation of acceleration, velocity, and distance is equal to zero.

ODE Method to Solve the Equation. (one of many methods)

Solve for $x(t)$, provide $a(t)+v(t)+x(t)=0$. (Same as finding $y$ in $y”+y’+y=0$.)

Rewrite as $x”(t)+x'(t)+x(t)=0$. Now you use the “Constant Coefficient Method.”

$$x=e^{rt},\qquad x’=re^{rt},\qquad x”=r^2e^{rt},\qquad r^2e^{rt}+re^{rt}+e^{rt}=0.$$
$$e^{rt}[r^2+r+1]=0 \ \Rightarrow\ e^{rt}>0,\qquad r^2+r+1=0.$$
$$r= \frac{-b\pm\sqrt{b^2-4ac}}{2a} = \frac{-1\pm\sqrt{(1)^2-4(1)(1)}}{2(1)} = \frac{-1\pm\sqrt{-3}}{2} = \frac{-1\pm i\sqrt{3}}{2} = -\frac{1}{2}\pm\frac{\sqrt{3}}{2}i.$$
$$\therefore\quad x(t)=e^{-\frac{1}{2}t} \left[ c_1\cos\left(\frac{\sqrt{3}}{2}t\right) + c_2\sin\left(\frac{\sqrt{3}}{2}t\right) \right].$$

The above equation (answer) models motion (distance/displacement), the derivatives are velocity (speed) and acceleration. This is how differential equations is in relation to physics.

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